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1z0-809-KR Latest Test Sample & 1z0-809-KR Test Simulator Fee - Latest 1z0-809-KR Study Guide - Kolis

  • Exam Number/Code : 1z0-809-KR
  • Exam Name : Java SE 8 Programmer II (1z0-809 Korean Version)
  • Questions and Answers : 260 Q&As
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NEW QUESTION: 1
Die folgenden Ledger sind Ihrem Buchungskreis in der Finanzbuchhaltung zugeordnet. Standard-Ledger A und B Erweiterungs-Ledger C mit Standard-Ledger A als. Welche Ledger werden in den universellen Journaleintragspositionen aufgeführt, nachdem Sie einen eingehenden ivocie eingegeben haben?
A. Nebenstellenbuch C.
Standardbuch B.
B. Standardbuch A.
Erweiterungsbuch C.
C. Standardbuch B.
D. Nebenstellenbuch C.
Standardbuch A.
E. Standardbuch A.
Standardbuch B.
Answer: E

NEW QUESTION: 2
You need to perform these tasks: Create and assign a MANAGER role to Blake and Clark Grant CREATE TABLE and CREATE VIEW privileges to Blake and Clark
Which set of SQL statements achieves the desired results?
A. CREATE ROLE manager;
GRANT create table, create voew
TO manager;
GRANT manager ROLE TO BLAKE, CLARK;
B. GRANT manager ROLE TO BLAKE, CLARK;
GRANT create table, create voew
TO BLAKE CLARK;
***MISSING***
C. CREATE ROLE manager;
GRANT create table, create view
TO manager;
GRANT manager TO BLAKE, CLARK;
Answer: C
Explanation:
Result of commands:


NEW QUESTION: 3
Identify the data structure with the following characteristics:
Contains one or more records per subject, per analysis parameter, and per analysis timepoint.
May be derived from findings, events, interventions and special-purpose SDTM domains, or other ADaM datasets.
A record can represent an observed, derived, or imputed value required for analysis.
A. Event Level Analysis Data Set (ADAE)
B. Basic Data Structure (BDS)
C. General Data Structure (GDS)
D. Subject Level Analysis Data Set (ADSL)
Answer: B

NEW QUESTION: 4
You administer a Microsoft SQL Server 2014 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)

You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format.

Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers-CustomerIdWHERE Customers.CustomerId = 1FOR XML RAW
B. SELECT Name AS `Customers/Name', CountryAS `Customers/Country', OrderId, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId= Customers.CustomerIdWHERE Customers.CustomerId= 1FOR XML PATH (`Customers'
C. SELECT Name, Country, Crderld, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId= Customers.CustomerIdWHERE Customers.CustomerId= FOR XML AUTO, ELEMENTS
D. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML RAW, ELEMENTS
E. SELECT Name AS `@Name', CountryAS `@Country', OrderId, OrderDate,
AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId
Customers.CustomerIdWHERE Customers.CustomerId= 1FOR XML PATH (`Customers')
F. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId = Customers.CustomerIdWHERE Customers.CustomerId = 1FOR XML AUTO
G. SELECT OrderId, OrderDate, Amount, Name, CountryFROM OrdersINNER JOIN CustomersON Orders.CustomerId*Customers.CustomerIdWHERE Customers.CustomerId
1FOR XML AUTO, ELEMENTS
H. SELECT Name, Country, Orderld, OrderDate, AmountFROM OrdersINNER JOIN CustomersON Orders.CustomerId= Customers.CustomerIdWHERE Customers.CustomerId= 1FOR XML AUTO, ELEMENTS
Answer: H

 

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